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(D) $1$. $(P)$ is $CH_3NH_2$ (methylamine,an aliphatic amine) and $(Q)$ is $PhNH_2$ (aniline,an aromatic amine).$2$. Aliphatic amines are more basic t

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Both $(P)$ and $(Q)$ can be obtained by Gabriel phthalimide synthesis

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(D) $1$. $(P)$ is $CH_3NH_2$ (methylamine,an aliphatic amine) and $(Q)$ is $PhNH_2$ (aniline,an aromatic amine).$2$. Aliphatic amines are more basic than aromatic amines due to the electron-donating effect of the alkyl group and resonance stabilization of the lone pair in aniline. Thus,$(P) > (Q)$ is correct.$3$. Both primary amines $(P)$ and $(Q)$ undergo the carbylamine reaction with $CHCl_3$ and $KOH$ to form foul-smelling isocyanides. This is correct.$4$. Both primary amines react with Hinsberg reagent $(PhSO_2Cl)$ to form $N$-substituted sulfonamides,which contain an acidic hydrogen on the nitrogen atom,making them soluble in alkali. This is correct.$5$. Gabriel phthalimide synthesis is used for the preparation of primary aliphatic amines. It cannot be used for the preparation of aromatic primary amines (like aniline) because aryl halides do not undergo nucleophilic substitution with the phthalimide anion under these conditions. Thus,option $(D)$ is incorrect.

For the following compounds,choose the incorrect option?
$CH_3-NH_2 \, \, (P)$
$Ph-NH_2 \, \, (Q)$

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For the following compounds,choose the incorrect option?$CH_3-NH_2 \, \, (P)$$Ph-NH_2 \, \, (Q)$